0x00：前言

  • 实现一个函数,参数为n,返回1(1+2)…*(1+2+…+n)的值

0x01：代码

package main

import "fmt"

func getSum(n int) (sum int) {
    sum := 1
    for i := 1; i <= n; i++ {
        sum1 := 0
        for j := 1; j <= i; j++{
            sum1 += j
        }
        sum = sum*sum1
    }
    return
}
func main(){
    for i := 1; i <= 5; i++ {
        fmt.Printf("n=%d,result:%d",i,getSum(i))
    }
}

0x02：运行结果

result

Last modification：June 25th, 2020 at 12:55 pm
© 允许规范转载
给狐宝打点钱⑧